Question

A solenoid has 80 cm length, number of loop is 4 and magnetic field inside it

        is 1.2 x 10 – 5T.  Find the current passing through the each loop of wire.

Answer 1

$B=μ_onI$

$μ_o=4\pi×10^-7$

$n=\frac{4}{0.8}=5$

$B=1.2×10^{-5}T$

$I=\frac{B}{μ_on}$

$I=\frac{1.2×10^{-5}}{4\pi×10^-7×5}=1.9A$