Answer to Question #290299 in Electric Circuits for Masyi

Question #290299

A 2µF capacitor is charged to 10 V, and then discharged through a 1.0 MΩ resistor.


a) What is the time constant of the discharge circuit? (Answer: 2 s)


b) What is the time taken for the potential difference across the capacitor to drop to 5 V? (Answer: 1.39


s)


1
Expert's answer
2022-01-25T07:09:04-0500

τ=RC=1×106×2×106\tau=RC=1×10^6×2×10^{-6}


=2seconds=2seconds


V=E(etRC)V=E(e^{\frac{-t}{RC}})


5=10(et2)5=10(e^\frac{-t}{2})


Solving for t,


t=1.3863 seconds





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