A 2µF capacitor is charged to 10 V, and then discharged through a 1.0 MΩ resistor.
a) What is the time constant of the discharge circuit? (Answer: 2 s)
b) What is the time taken for the potential difference across the capacitor to drop to 5 V? (Answer: 1.39
s)
"\\tau=RC=1\u00d710^6\u00d72\u00d710^{-6}"
"=2seconds"
"V=E(e^{\\frac{-t}{RC}})"
"5=10(e^\\frac{-t}{2})"
Solving for t,
t=1.3863 seconds
Comments
Leave a comment