Question #259112

1.       The maximum frequency deviation of the carrier is ± 15 kHz and the maximum modulating frequency is 3 kHz, calculate for the modulation index.

2.       Assume that the 60-dB bandwidth of a receiver is 12 kHz and the 6-dB bandwidth is 7 kHz. What is the shape factor of the circuit?

3.       What is the bandwidth of a receiver with a quality factor of 50 and a resonance frequency of 540 kHz.

4.       What is the maximum bandwidth of an FM signal with a deviation of 27 kHz and a maximum modulating signal of 4 kHz as determined by Carson’s rule?

5.       A PM signal has a maximum allowed deviation of 17 kHz and an actual deviation of 8 kHz. What is the percentage modulation?


1
Expert's answer
2021-11-04T13:38:37-0400

Solution;

(1)

Given;

Maximum frequency deviation,δmax=15kHz\delta_{max}=15kHz

Maximum modulating frequency,fm=3kHzf_m=3kHz

The modulations index,mfm_f ;

mf=δmaxfm=153=5m_f=\frac{\delta_{max}}{f_m}=\frac{15}{3}=5

(2)

Shape factor,SF, is the ratio of two bandwidth;

SF=BW60dBBW6dB=127=1.714SF=\frac{BW_{60-dB}}{BW_{6-dB}}=\frac{12}{7}=1.714


(3)

BW=frQ=540kHz50=10.8kHzBW=\frac{f_r}{Q}=\frac{540kHz}{50}=10.8kHz

(4)

By Carson's rule;

BWmax=2(δmax+fm)BW_{max}=2(\delta_{max}+f_m)

BWmax=2(27+4)=62kHzBW_{max}=2(27+4)=62kHz

(5)

Percentage modulation=δactualδmax×100\frac{\delta_{actual}}{\delta_{max}}×100

=817×100\frac{8}{17}×100 =47.0647.06 %








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