Question #258846

A PM signal has a maximum allowed deviation of 22 kHz  and an actual deviation of 5 kHz . What is its percent modulation?



1
Expert's answer
2021-11-01T19:28:34-0400

We know that

%modulation =actualdeviationalloweddeviation×100\frac{actual deviation}{allowed deviation}\times100

% modulation=522×100=22.72\frac{5}{22}\times100=22.72 %


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