Question #258443

Spring constant of 0.13Kn/M. Solve the stretched (x) by forces. F1=13 N

1
Expert's answer
2021-10-31T18:22:31-0400

F=Kx

x=Fkx=\frac{F}{k}

x=130.13×103=0.1mx=\frac{13}{0.13\times10^{3}}=0.1m



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