Capacitance, C = 1 farad
Current, I = 10 A
Time, t = 20 s
Formula used:
Charge, q = current x time
Energy stored in the capacitor
U=U =U= q22C\frac{q^2}{2C}2Cq2
So, the charge, q = 10 x 20 = 200 C
Energy stored is
U=200×2002×1U=20000JU=\frac{200\times 200}{2\times 1}\\ \\ U=20000 JU=2×1200×200U=20000J
Answer:
The energy stored in the capacitor is 20000 J.
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