Question #206591
  • A 1 capacitance is charged using a constant of 10 for 20 seconds . What is the energy finally stored by the capacitor
1
Expert's answer
2021-06-14T14:09:03-0400

Solution: Given:

Capacitance, C = 1 farad

Current, I = 10 A

Time, t = 20 s

Formula used:

Charge, q = current x time

Energy stored in the capacitor

U=U = q22C\frac{q^2}{2C}

So, the charge, q = 10 x 20 = 200 C

Energy stored is

U=200×2002×1U=20000JU=\frac{200\times 200}{2\times 1}\\ \\ U=20000 J

Answer:

The energy stored in the capacitor is 20000 J.


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