The given problem can be shown in below diagram:

R1 = 12 Ohms and R2 = 15 Ohms are in series,
Therefore, equivalent resistance R = R1 + R2
R = 12 + 15 = 27 Ohms
Voltage V = 9V
Therefore, the current I is given by:
CurrentI=RV=279=0.33Amp.
Hence the current in the circuit is I = 0.33 Amp.
Comments