Question #196330

If two coils are connected in series and have resistance of 400 ohms and 200 ohms with temperature coeffetients of 0.1% and 0.4% respectively at 20 degrees Celsius. What is the temperature coefficient of the combination, and what is the resistance of the combination at 50 degrees Celsius?


1
Expert's answer
2021-05-21T10:42:42-0400

Resistance, R1=400 ΩR_1=400\space\Omega

α1=0.001\alpha_1=0.001

Resistance, R2=200 ΩR_2=200\space\Omega

α2=0.004\alpha_2=0.004

Equivalent Resistance, Req=R1+R2=600 ΩR_{eq}=R_1+R_2=600\space \Omega

Initial temperature, T1=20°CT_1=20\degree C

Final temperature, T2=50°CT_2=50\degree C

ΔT=30°C\Delta T=30\degree C

temperature coefficient of the combination,

α=R1α1+R2α2R1+R2=0.002\alpha=\dfrac{R_1\alpha_1+R_2\alpha_2}{R_1+R_2}=0.002


resistance of the combination at 50 degrees Celsius,

Rf=Req(1+αΔT)R_f=R_{eq}(1+\alpha\Delta T)

Rf=646 ΩR_f=646\space\Omega


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