Answer to Question #196038 in Electric Circuits for Kenma

Question

Find the current through a loop needed to create a maximum torque of 18 N⋅m. The loop has 132 square turns that are 18.7 cm on a side and is in a uniform 0.242-T magnetic field.

answer to 2 decimal places

Answer 1

Gives

Torques$\tau=18Nm$

Side square (l)=18.7cm

Magnetic field (B)=0.242T

Magnetic moment

$M=NIA$

$\tau=M\times B$

$\tau=NIABsin\theta$

$sin90°=1$

$I=\frac{\tau}{NAB}$

Put value

$I=\frac{18}{132\times(18.7\times10^{-2})^2\times0.242}$

$I=16.11A$