Question #196715

Calculate the energy transferred in bulb X in 3Seconds if the current in the circuit is 2 Amperes


1
Expert's answer
2021-05-23T18:57:00-0400

Gives

Time(t)=3sec

Current (i)=2Amp

Resistance=x ohm

Power


P=i2XP=i^2X

Energy transfer in 💡(bulb)

P=EtP=\frac{E}{t}

E=P×tE=P\times t

E=i2XtE=i^2Xt

Put values

E=22×3XE=2^2\times3X

E=12XJE=12XJ


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