Calculate the energy transferred in bulb X in 3Seconds if the current in the circuit is 2 Amperes
Gives
Time(t)=3sec
Current (i)=2Amp
Resistance=x ohm
Power
P=i2XP=i^2XP=i2X
Energy transfer in 💡(bulb)
P=EtP=\frac{E}{t}P=tE​
E=P×tE=P\times tE=P×t
E=i2XtE=i^2XtE=i2Xt
Put values
E=22×3XE=2^2\times3XE=22×3X
E=12XJE=12XJE=12XJ
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