Question

two identical incandescent light bulbs, each with resistance R=2Ω, are connected to as source with E= 8V and negligible internal resistance. find the current through each bulb is the bulb are connected in series.

Answer 1

Bulbs are connected in series.

Resistance of each bulb, $R = 2 \Omega$

Total resistance of the circuit, $R_T = 2+2 = 4 \Omega$

Potential in the circuit, $E = 8V$

Total current in circuit, $I = \frac{E}{R_T} = \frac{8}{4} = 2A$

Since bulbs are in series, so current through each bulbs is same i.e. 2A.