(a) Star connection
Inductive reactance
"X_L = 2\u03c0fL \\\\\n\nX_L = 2\u03c0 \\times 50 \\times 42 \\times 10^{-3} = 13.19 \\;\u03a9"
Phase impedance
"Z_{ph} = \\sqrt{R^2 + X_L^2} \\\\\n\nZ_{ph} = \\sqrt{15^2 + 13.19^2} = 19.97"
Line voltage
"V_{line} = \\sqrt{3}V_{ph} \\\\\n\nV_{ph} = \\frac{V_{line}}{\\sqrt{3}} = \\frac{415}{\\sqrt{3}} = 240 \\;volts"
Phase current
"I_{ph } = \\frac{V_{ph}}{Z_{ph}} \\\\\n\nI_{ph} = \\frac{240}{19.97} = 12.02 \\;A"
Line current
"I_{line} = I_{ph} = 12.02 \\;A"
Dissipated power
"P = 3I_{line}^2R \\\\\n\nP = 3 \\times (12.02)^2 \\times 15 = 6.6 \\;kW"
(b) Delta connection
"V_{line} = V_{ph} = 415 \\;V \\\\\n\nZ_{ph} = 19.97 \\\\\n\nI_{ph} = \\frac{V_{ph}}{Z_{ph}} \\\\\n\nI_{ph} = \\frac{415}{19.97} = 20.78 \\;A"
Dissipated power
"P = \\sqrt{3}I_{ph}^2R \\\\\n\nP = \\sqrt{3} \\times 20.78^2 \\times 15 = 11.22 \\;kW"
Comments
The way the problem solved is very good and l appreciate it. Thanks
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