Answer to Question #147805 in Electric Circuits for Barigbue

Question

Three charges of +5c , -10c and -8c are distributed as shown below.....
Calculate the resultant force acting on the 5c

Answer 1

We have three charges: +5, -10, -8.

the formula of force acting between two charges is F = $\frac{ k*q1*q2}{r2}$ ;

There are two charges whch are force acting with +5c. these are -10, -8. Let's consider the location of charges in series and the distance of two charges which are in series r.

F₊₅ = F₁ + F₂ ; k = 8.99x10⁹ Nm²/C².

F₁= $\frac{8.99 * 5c * 10c}{ r2}$ x10⁹ Nm²/C² = $\frac{4.495}{ r2}$ * 10¹¹  N.

F₂= $\frac{8.99 * 5c * 8c}{ r2}$ x10⁹ Nm²/C² = $\frac{3.596}{ r2}$ * 10¹¹ N.

F= F₁ + F₂ = $\frac{4.495}{ r2}$ * 10¹¹  N + $\frac{3.596}{ r2}$ * 10¹¹ N = $\frac{8.091}{ r2}$ * 10¹¹ N.