Answer
a. power is delivered to the motor
Is given by
P=VI=12×0.75=9P=VI=12\times0.75=9P=VI=12×0.75=9 Watts
b. If the motor runs for 5.0 min, then electrical
energy is delivered as
P=EtP=\frac{E}{t}P=tE
So energy is
E=Pt=9×60=540JE=Pt=9\times60=540JE=Pt=9×60=540J
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