As per the given question,
Rs=18−1210×10−3=610−2=600ΩR_{s}=\dfrac{18-12}{10\times 10^{-3}}=\dfrac{6}{10^{-2}}=600\OmegaRs=10×10−318−12=10−26=600Ω
Wattage of zenar diode (P)=VI(P)=VI(P)=VI
=12×10×10−3=0.12watt=12\times 10\times 10^{-3}=0.12 watt=12×10×10−3=0.12watt
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