Answer to Question #111441 in Electric Circuits for Trevor Collins

Question #111441
There is a circuit with an inductor and two capacitors in series. Each capacitor is adjacent to the inductor. Capacitor 1 has charge Q1 and Capacitor 2 has charge Q2. Current is moving in the clockwise direction check this figure

https://www.chegg.com/homework-help/questions-and-answers/case-difficult-read-charges-right-capacitor-q2-q2-q37457186

We are asked to derive a formula for the resonant frequency.
1
Expert's answer
2020-04-23T12:45:43-0400

Solution: In the figure, two capacitors are connected in series and in series with inductance. The impedance of the circuit with alternating current frequency "w" can be written as.

(1) "Z(w)=iwL+\\frac {1}{iwC_1}+\\frac {1}{iwC_2}"

Find the magnitude of impedance (1)

(2) "|Z(w)|=|i(Lw-\\frac{C_1 + C_2}{w C_1\\cdot C_2})|=|Lw-\\frac{C_1 + C_2}{w C_1\\cdot C_2}|" .

Resonance in a sequential circuit is achieved at a frequency at which "|Z(w)|\\to min". In our case of the absence of resistive elements the exact condition must be met "|Z(w)|=0", that is

(3) "Lw_r-\\frac{C_1 + C_2}{w_r C_1\\cdot C_2}=0"

From (3) we determine the resonant frequency "w_r"

(4) "w_r=\\sqrt{\\frac{C_1+C_2}{L\\cdot C_1\\cdot C_2}}"

The initial charges of the capacitors do not affect the resonant frequency of the circuit. Expression (4) corresponds to the well-known formula of the oscillatory contour "w_r=\\frac{1}{\\sqrt{LC}}" if we take into account (5) "C=\\frac{C_1\\cdot C_2}{C_1+C_2}" for the capacity of serial capacitors.

This formula can be obtained from the following consideration. When connected in series, electrical voltages of the components are added to each other. "U=U_1+U_2" . According to the capacity definition we have "U_1=\\frac {Q_1}{C_1}", "U_2=\\frac {Q_2}{C_2}" and If they change over time "U(t)=\\frac{Q_1(t)}{C_1}+\\frac{Q_2(t)}{C_2}" . The current or what is the same amount of charge flowing per unit of time through the capacitors in a serial circuit is the same i.e. "I(t)=\\frac{dQ_1(t)}{dt}=\\frac{dQ_2(t)}{dt}" . This means that

(6) "\\dot{U}(t)=I(t)\\cdot (\\frac{1}{C_1}+\\frac{1}{C_2})" . The voltage in the AC circuit is written as "U(t)=U(w)\\cdot e^{iwt}" and has a time derivative "\\dot{U}(t)=iw\\cdot U(w)\\cdot e^{iwt}" substitute to (6) we get

(7) "U(w)=I(w)\\cdot (\\frac{1}{iwC_1}+\\frac{1}{iwC_2})" when "I(t)=I(w)\\cdot e^{iwt}" , and the multiplier "e^{iwt}" has decreased.

Using the definition of impedance "Z(w)=\\frac{U(w)}{I(w)}" we get (1) and (5).

Answer:  The formula for the resonant frequency is "w_r=\\sqrt{\\frac{C_1+C_2}{L\\cdot C_1\\cdot C_2}}"


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