"P=IU, I=\\frac {U}{R}\n \\implies\\\\\nP=\\frac{U^2}{R}\\implies\nU=\\sqrt{PR}\\implies\\\\\nU=\\sqrt{10\\cdot250}=\\sqrt{2500}=50 \\textnormal{v}\\\\\nanswer: U=50\\textnormal{volt}"
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