Classical Mechanics Answers

As polar ice melts, there will be a huge transfer of weight to the equator. what will this do to gravity, and plate tectonics

find the x and y components of a 400 N force at an angle of 125 to the x-axis

Solve for the tension in cable BC and CE in the figure if the boz weighs 150N.

Figure: https://ibb.co/ryD89Km

an earth satellite,in circular orbit at an altitude h of 230 km above the earth's surface,has a period T of 89 minutes.What mass of the earth follows from these data?

What is the total energy (E) of a 2.53 MeV electron?( When energy is used as an adjective, it refers to the kinetic energy of the particle, K= 2.53 MeV.)

the angular momentum J of a particle is given as J=8t^4i-2t^2j+12t^3k,find the torque at t=1.
(i should confirm that it is 8t the power of 4 likewise take others powers also)

A pedestrian is running at his maximum speed of 6.0 m/sec to catch a bus stopped at a traffic light. When his is 15m from the bus, the light changes and the bus accelerates uniformly at 1m/s/s. Does he make it to the bus? If so , how far does he have to run in order to catch it? If not, how close does he get?

A pedestrian is running at his maximum speed of 6.0 m/sec to catch a bus stopped at a traffic light. When his is 15m from the bus, the light changes and the bus accelerates uniformly at 1m/s/s. Does he make it to the bus? If so , how far does he have to run in order to catch it? If not, how close does he get?

a ball player catches a ball 3.53 seconds after throwing it vertically upward.
- with what speed did he throw it?
-what height did it reach?

I was given this problem: "A 50kg object was held 10m above water, when it was dropped, find the velocity when it reached the surface of the water, and if the object stopped 2.45m under the surface of the water, find the water resistance force."

I was able to solve the first part and find the velocity, which was 14 m/s, but I'm struggling to solve the second part.

The answer my book gave was -2000N for the water resistance, and I don't understand how that is true.

My understanding is that using the equations of motion I could find the acceleration of the object under water, which is -40 m/s², and this means that the net force that is affecting the object is -2000N, and the weight is 490N, so now the resistance must be -2490N? But the book says it's -2000N and I don't know how!