2019-06-09T12:33:22-04:00
the angular momentum J of a particle is given as J=8t^4i-2t^2j+12t^3k,find the torque at t=1.
(i should confirm that it is 8t the power of 4 likewise take others powers also)
1
2019-06-10T09:59:11-0400
The torque is
τ = d J d t \tau=\frac{dJ}{dt} τ = d t dJ
τ = d d t ( 8 t 4 i − 2 t 2 j + 12 t 3 k ) \tau=\frac{d}{dt} (8t^4\bold{i}-2t^2\bold{j}+12t^3\bold{k}) τ = d t d ( 8 t 4 i − 2 t 2 j + 12 t 3 k )
τ = ( 8 ( 4 ) t 3 i − 2 ( 2 ) t j + 12 ( 3 ) t 2 k ) \tau= (8(4)t^3\bold{i}-2(2)t\bold{j}+12(3)t^2\bold{k}) τ = ( 8 ( 4 ) t 3 i − 2 ( 2 ) t j + 12 ( 3 ) t 2 k )
τ ( 1 ) = 32 i − 4 j + 36 k \tau(1)= 32\bold{i}-4\bold{j}+36\bold{k} τ ( 1 ) = 32 i − 4 j + 36 k
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