The information given is
The period of a complete orbit is T=1.9×106s
The average radius of the orbit is. r=1.6×109s
Considering the circular orbit.
The angular speed is given by
w=T2πrad
Where.
2πrad is the angular displacement of a complete orbit
T is the period of a complete orbit.
Evaluating numerically.
w=T2πradw=1.9×106s2πradw=3.3×10−6rad/s
The centripetal acceleration is given by.
ac=w2r
Where.
w is the angular speed
r is the radius.
Evaluating numerically.
ac=w2rac=(3.3×10−6rad/s)2×1.6×109sac=1.7×10−2m/s2
Answer A
The centripetal acceleration is ac=1.7×10−2m/s2
Part b
The linear velocity is given by
V=w⋅r
Where
w is the angular speed
r is the radio
Evaluating numerically
V=w⋅rV=3.3×10−6rad/s×1.6×109sV=5.3×103m/s
Answer B
The velocity is V=5.3×103m/s
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