Obtain the corresponding potential energy function of the intermolecular force. 1. F(r) = -ar^-7 + br^-9. 2. at what value of 'r' will the potential energy function be minimum
F(r)=−ar−7+br−9,F(r)=-ar^{-7}+br^{-9},F(r)=−ar−7+br−9,
F′(r)=7ar8−9br10=7ar2−9br10,F'(r)=\frac{7a}{r^8}-\frac{9b}{r^{10}}=\frac{7ar^2-9b}{r^{10}},F′(r)=r87a−r109b=r107ar2−9b,
F′(r)=0,F'(r)=0,F′(r)=0,
rmin=9b7a.r_{min}=\sqrt{\frac{9b}{7a}}.rmin=7a9b.
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