Answer to Question #189949 in Classical Mechanics for FRANS

Question #189949

We have a Cavendish balance set up with two spheres (one small and one large) that are five centimeters apart of masses m = 1 g and m0 = 500 m, respectively. Suppose these design is placed at a point in space far removed from all other bodies. ,→ What is the acceleration a of the body m, and the acceleration a 0 of the body m0 ? [15] ,→ Is this a constant acceleration problem? Explain why or why not!


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Expert's answer
2021-05-07T06:41:14-0400
a=(6.671011)500(0.001)0.052=1.3108ms2a=(6.671011)(0.001)0.052=2.71011ms2a=(6.67\cdot10^{-11})\frac{500(0.001)}{0.05^2}=1.3\cdot10^{-8}\frac{m}{s^2}\\ a'=(6.67\cdot10^{-11})\frac{(0.001)}{0.05^2}=2.7\cdot10^{-11}\frac{m}{s^2}

No. The acceleration will change with distance.


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