Answer to Question #189497 in Classical Mechanics for Jethro

Question #189497

A bar 2 m long makes an angle of 30° with the horizontal. A force of 40 is applied 0.4 m from the upper end. Calculate the torque due to this a force about each end.


1
Expert's answer
2021-05-09T13:06:54-0400
τupper=(40)(0.4)cos30=13.9 Nmτlower=(40)(1.6)cos30=55.4 Nm\tau_{upper}=(40)(0.4)\cos{30}=13.9\ Nm\\ \tau_{lower}=(40)(1.6)\cos{30}=55.4\ Nm


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