Question

A bar 2 m long makes an angle of 30° with the horizontal. A force of 40 is applied 0.4 m from the upper end. Calculate the torque due to this a force about each end.

Answer 1

$$\tau_{upper}=(40)(0.4)\cos{30}=13.9\ Nm\\ \tau_{lower}=(40)(1.6)\cos{30}=55.4\ Nm$$