Answer to Question #189358 in Classical Mechanics for Chinmoy Das

Question #189358

Let's assume a rigid body of mass "m" has a velocity(ai^+bj^) in two dimensional plane and is now at the position (x1,y1) . It is experiencing a constant force "F" towards the origin(0,0).

What are the conditions for the body to orbit the origin?


1
Expert's answer
2021-05-05T17:50:48-0400

Given,

Mass of rigid body =m=m

Velocity (v)=(ai^+bj^)(v)=(a \hat{i}+b\hat{j})

Position of the body (x1,y1)(x_1, y_1)

r^=x1i^+y1j^\hat{r}=x_1\hat{i}+y_1\hat{j}

Constant force = F is towards the origin (0,0)

F=m(a2+b2)2(x1)2+(y1)2\Rightarrow F=m\frac{(\sqrt{a^2+b^2})^2}{\sqrt{(x_1)^2+(y_1)^2}}


F=ma2+b2x12+y12\Rightarrow F = m\frac{a^2+b^2}{\sqrt{x_1^2+y_1^2}}

Hence, the centripetal force will be F.


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