Question #189288

6. The average speed of a nitrogen molecule in air is about

6.70 1 102 m/s, and its mass is 4.68 1 10#26 kg. (a) If it

takes 3.00 1 10#13 s for a nitrogen molecule to hit a wall

and rebound with the same speed but moving in the op-

posite direction, what is the average acceleration of the

molecule during this time interval? (b) What average

force does the molecule exert on the wall?


1
Expert's answer
2021-05-05T16:05:20-0400

Given,

Velocity(v1)=6.70×102m/s(v_1)=6.70\times 10^{2} m/s

After the hitting the wall, it rebounds with the same speed in opposite direction,

v2=6.7×102m/sv_2=-6.7\times 10^{2}m/s


Mass (m)=4.68×1026kg(m)=4.68\times 10^{-26}kg


Time (t)=3.0×1013s(t)=3.0\times 10^{-13}s


a=dvdt=v2v1ta=\frac{dv}{dt}=\frac{v_2-v_1}{t}


=6.7×1026.7×1023.0×1013m/s2=\frac{-6.7\times 10^2-6.7\times 10^2}{3.0\times 10^{-13}} m/s^2


=4.47×1015m/s2=-4.47\times10^{15} m/s^2

Average force (F)=ma(F)= ma


F=4.68×1026×4.47×1015NF=4.68\times 10^{-26}\times 4.47\times 10^{15}N

=20.91×1011N=20.91\times 10^{-11}N


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