As per D'Alembert Principle, the sum of incremental virtual works done by all external forces (F) acting in conjunction with virtual displacement.
As per the question,
mass of the car "(m)=1200kg"
slop of the rod "(\\tan \\theta)=\\dfrac{1}{6}"
"\\sin \\theta =\\dfrac{1}{\\sqrt{37}}" ,
"\\cos \\theta=\\dfrac{6}{\\sqrt{37}}"
initial speed "(u)=10 kmph =10\\times \\dfrac{1000}{3600}=\\dfrac{25}{9} m\/sec"
final speed "(v)=60kmph =60\\times \\dfrac{1000}{3600}=\\dfrac{50}{3} m\/sec"
distance covered along the road "(d)=120m"
Frictional resistance force "(f)=800N"
acceleration of the block "=\\dfrac{v^2-u^2}{2s}=\\dfrac{(\\dfrac{50}{3})^2-(\\dfrac{25}{9})^2}{2\\times 120}=\\dfrac{268.27}{240}=1.12m\/sec^2"
so F =ma
"F=1200\\times 1.12 =1344 N"
Hence, work done "(W)=F.d = 1344\\times 120=161280J"
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