Question #114809
A car is moving around a banked curve of radius 86 m at a constant speed. The road is banked at an angle of 11° and the car is moving at just the correct speed to ensure that there are no lateral frictional forces on the tyres - that is the only forces acting on the car are the force of gravity and the normal force from the road.

At what speed is the car moving? (in m s−1 to 2 s.f
1
Expert's answer
2020-05-08T16:28:08-0400

As per the question,

Radius of the curvature of the road (R)=86m

The banking of the road (θ)=11(\theta)=11^\circ

Now, applying the force balance rule,

mgsinθ=mv2cosθRmg\sin \theta =\dfrac{mv^2\cos \theta}{R}

v=Rgsinθcosθ\Rightarrow v=\sqrt{\dfrac{Rg \sin \theta}{\cos \theta}}

Now, substituting the values,

v=163.82m/sec=12.79m/sec=12.8m/secv=\sqrt{163.82}m/sec=12.79 m/sec = 12.8 m/sec


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS