As per the question,
Radius of the curvature of the road (R)=86m
The banking of the road "(\\theta)=11^\\circ"
Now, applying the force balance rule,
"mg\\sin \\theta =\\dfrac{mv^2\\cos \\theta}{R}"
"\\Rightarrow v=\\sqrt{\\dfrac{Rg \\sin \\theta}{\\cos \\theta}}"
Now, substituting the values,
"v=\\sqrt{163.82}m\/sec=12.79 m\/sec = 12.8 m\/sec"
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