A)
as the mass is under free-fall condition so we can apply equation "v^2=u^2+2gh"
"v^2=0+2\\times10\\times6=120"
"v=2\\sqrt{30}m\/s"
B)
applying mechanical energy conservation
"K_i+U_i=K_f+U_f\\\\\\frac12\\times2\\times120+0=0+\\frac12\\times k\\times x^2"
"240=500\\times x^2"
"x=0.69m"
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