As per the given question,
Spring constant"(k)= 1000N\/m."
Compression distance "(x)=15cm"
Mass of the object "(m)=200g=0.2 kg"
Angle of inclination of the plane "(\\theta)=30^\\circ"
Coefficient of kinetic friction "(\\mu)=0.2"
let l is the distance traveled on the inclined plane
Applying the conservation of energy,
"\\Rightarrow \\dfrac{kx^2}{2}=mg\\sin\\theta \\times l"
"\\Rightarrow l =\\dfrac{kx^2}{2mg\\sin\\theta}=\\dfrac{1000\\times 0.15\\times 0.15}{2\\times 0.2 \\times 9.8 \\times \\sin 30}"
"\\Rightarrow l =\\dfrac{225}{1.96}=114.8m"
and height raised by block =57.4m"=l\\sin\\theta =57.4m"
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