Part(a)
Total energy of first excited state
E=−2213.6=−3.4eV
For H atom Z=1
Kinetic energy H atom
K=−(−3.4)=3.4eV
Potential energy
E=K+UU=E−K
U=−3.4−3.4=−6.8eV
Part(b)
Ground state energy
E=n2−13.6 eV
n=1 ground state
E=12−13.6=−13.6eV
First excited state
E=−3.4eV
∆E=E1−E2
∆E=−3.4−(−13.6)=10.2eV ∆E=λhc
λ=∆Ehc
λ=10.2×1.6×10−196.625×10−34×3×108=121.78×10−9=121.78nm
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