Answer to Question #270379 in Atomic and Nuclear Physics for John Drix

Question

Activity 3: Gravitational Force

The mass of m1 of one of the small sheres of a Cavendish balance is 0.02 kg, the

mass m2 of the nearest large sphere is 0.065 kg, and the center-to-center distance

between them is 0.04 m. Find the gravitational force Fg on each sphere due to the other.

Answer 1

$m_1=0.02kg\\m_2=0.065kg\\r=0.04m$

Gravitation force

$F=\frac{Gm_1m_2}{r^2}$

$$F=\frac{6.67\times10^{-11}\times0.02\times0.065}{0.04^2}=5.41\times10^{-11}N$$