Question #270379

Activity 3: Gravitational Force



The mass of m1 of one of the small sheres of a Cavendish balance is 0.02 kg, the



mass m2 of the nearest large sphere is 0.065 kg, and the center-to-center distance



between them is 0.04 m. Find the gravitational force Fg on each sphere due to the other.

1
Expert's answer
2021-11-23T17:18:42-0500

m1=0.02kgm2=0.065kgr=0.04mm_1=0.02kg\\m_2=0.065kg\\r=0.04m

Gravitation force

F=Gm1m2r2F=\frac{Gm_1m_2}{r^2}


F=6.67×1011×0.02×0.0650.042=5.41×1011NF=\frac{6.67\times10^{-11}\times0.02\times0.065}{0.04^2}=5.41\times10^{-11}N


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