A 0.15kg tumor is treated with α
α particles. There are 2×10
12
2×1012 particles reaching the tumor every second, each having energy 3×10
−15
3×10−15J. What is the absorbed dose given to the tumor
D=Em=nE0m=0.04 Gy.D=\frac Em=\frac{nE_0}m=0.04~Gy.D=mE=mnE0=0.04 Gy.
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