A 2.0kg piece of meat is treated with 1.5kGy in order to kill bacteria and preserve its shelf life. How much energy is absorbed by the meat?
D=Em, ⟹ E=mD,D=\frac Em,\implies E=mD,D=mE,⟹E=mD,
E=2⋅1500=3 kJ.E=2\cdot 1500=3~kJ.E=2⋅1500=3 kJ.
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