What is the coefficient of kinetic friction between the 100 N and 39 ⁰
Given: mass (m)=100 kg
Force (F)=100 N and acceleration due to gravity (g)=10 m/s2m/s^2m/s2
Now we know that F=ukmgF=u_{k} m gF=ukmg
100=uk×100×10∴uk=1001000uk=0.10100 =u_{k} \times 100 \times 10\\ \therefore u_{k}=\frac{100}{1000} \\ u_{k}=0.10100=uk×100×10∴uk=1000100uk=0.10
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