Answer to Question #168711 in Atomic and Nuclear Physics for Lara

Question

One of the uranium 235 nuclear fission reactions in a nuclear reactor is the following: n¹_{0 + U}²³⁵_{92 = Zr}⁹¹ _{40 + La}¹⁴²_{58 + x n}¹_{0 + y e}⁰_{-1 . Determine the number of x neutrons and the number of y neutrons produced by this reaction.}

Answer 1

La has a number 57 is the periodic table, 58 is Ce.

$\frac{1}{0}n + \frac{235}{92}U = \frac{91}{40}Zr + \frac{142}{57}La + 3\frac{1}{0}n + 5\frac{0}{-1}e$