Answer to Question #168622 in Atomic and Nuclear Physics for Sani

Question #168622

Derive the expression of the Q = ΔE of a nuclear reaction, hence, determine the Q value and the nature of the reaction F19 (H1,α) O16( 18.998405u, 15.994915u, 4.002603u, 1.007825u are masses of F19, O16, α, H1) respectively.


1
Expert's answer
2021-03-04T11:53:39-0500
H1+F19He4+O16+QH^1+F^{19}\to He^4+O^{16}+Q

1.007825+18.998405=4.002603+15.994915+Q1.007825+18.998405\\=4.002603+15.994915+Q

Q=0.008712 u=+8.11 MeVQ=0.008712\ u=+8.11\ MeV

The reaction is exoergic.


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