Question

Derive the expression of the Q = ΔE of a nuclear reaction, hence, determine the Q value and the nature of the reaction F19 (H1,α) O16( 18.998405u, 15.994915u, 4.002603u, 1.007825u are masses of F19, O16, α, H1) respectively.

Answer 1

$$H^1+F^{19}\to He^4+O^{16}+Q$$

$$1.007825+18.998405\\=4.002603+15.994915+Q$$

$$Q=0.008712\ u=+8.11\ MeV$$

The reaction is exoergic.