Question #168426

An 'α' particle has an initial velocity of (12 km/s)ˆj+ (15 km/s)ˆkand aconstant acceleration of (2×108m/s2)ˆi in a region where there are uniform electricand magnetic fields. If~B= (4×10−4,0,0) T, what is~E?


1
Expert's answer
2021-03-09T10:58:38-0500
F=ma=qE+qv×Bv×B=(12000,15000,0)×(4104,0,0)=(0,0,6)\bold{F =ma= qE + qv × B}\\\bold{v × B}=(12000,15000,0)×(4\cdot10^{-4},0,0)\\=(0,0,-6)

(6.641027)(2108,0,0)=(3.221019)E+(3.221019)(0,0,6)(6.64\cdot10^{-27})(2\cdot10^8,0,0)= (3.22\cdot10^{-19})E \\+ (3.22\cdot10^{-19})(0,0,-6)

E=(4.1,0,6)Vm\bold{E}=(4.1,0,6)\frac{V}{m}


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