Answer to Question #90279 in Astronomy | Astrophysics for Shivam Nishad

Question #90279
Assume that sun radiates like a black body of temperature T. Calculate T using Stefan-Boltzmann law. Take Q=5.67 x 10^-8 Wm^-2K^-4 and Lo=4 x 10^26 W.
1
Expert's answer
2019-06-03T10:35:51-0400

Stefan-Boltzmann law states, that the total energy radiated per unit surface area of a black body across all wavelengths per unit time (the black-body radiant emittance) is directly proportional to the fourth power of the black body's thermodynamic temperature T:


PA=σT4\frac{P}{A}=\sigma {{T}^{4}}

where P=41026WP=4\cdot {{10}^{26}}W  is the power of Sun, A=4πR2A=4\pi R_{\odot }^{2} is the surface area of Sun, R=7108m{{R}_{\odot }}=7\cdot {{10}^{8}}m is the Solar radius. Then we find


T4=P4πR2σ{{T}^{4}}=\frac{P}{4\pi R_{\odot }^{2}\cdot \sigma }

or


T=P4πR2σ4T=\sqrt[4]{\frac{P}{4\pi R_{\odot }^{2}\cdot \sigma }}

Substitute known values


T=41026W4π(7108m)25.67108Wm2K445800KT=\sqrt[4]{\frac{4\cdot {{10}^{26}}W}{4\pi {{\left( 7\cdot {{10}^{8}}m \right)}^{2}}\cdot 5.67\cdot {{10}^{-8}}W\cdot {{m}^{-2}}\cdot {{K}^{-4}}}}\approx 5800K

So the Sun has a surface temperature of 5800 K.


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