Question #90274

A galaxy of absolute magnitude M= - 20 is at a distance of 700 kpc. Would it be visible to the unaided eye.

Expert's answer

The apparent magnitude mm of an object is related to its absolute magnitude MM by the formula

m=M+5log10d10pc,m = M + 5 \log_{10} \frac{d}{10\,\text{pc}} \, ,

where dd is the distance to the object. Substituting the numbers M=20M = - 20 and d=700kpc=7×105pcd = 700\, \text{kpc} = 7 \times 10^5\, \text{pc} into this formula, we obtain m4.2m \approx 4.2. Since the dimmest objects visible to the unaided eye are assigned m=6m = 6, our galaxy would be visible.


Answer: yes.


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