Question #90274
A galaxy of absolute magnitude M= - 20 is at a distance of 700 kpc. Would it be visible to the unaided eye.
1
Expert's answer
2019-06-03T10:08:48-0400

The apparent magnitude mm of an object is related to its absolute magnitude MM by the formula

m=M+5log10d10pc,m = M + 5 \log_{10} \frac{d}{10\,\text{pc}} \, ,

where dd is the distance to the object. Substituting the numbers M=20M = - 20 and d=700kpc=7×105pcd = 700\, \text{kpc} = 7 \times 10^5\, \text{pc} into this formula, we obtain m4.2m \approx 4.2. Since the dimmest objects visible to the unaided eye are assigned m=6m = 6, our galaxy would be visible.


Answer: yes.


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