Question #144323
To show that sin^2x+cos^2x=1 is equivalent to tan^2x+1=sec^2x,

what do you need divide sin^2x+cos^2x=1 by?
1
Expert's answer
2020-11-17T17:03:05-0500

Let us divide both parts of the equality sin2x+cos2x=1\sin^2x+\cos^2x=1 by cos2x\cos^2 x. Then we have sin2x+cos2xcos2x=1cos2x\frac{\sin^2x+\cos^2x}{\cos^2 x}=\frac{1}{\cos^2{x}} which is equivalent to sin2xcos2x+cos2xcos2x=(1cosx)2\frac{\sin^2x}{\cos^2 x}+\frac{\cos^2x}{\cos^2 x}=(\frac{1}{\cos{x}})^2 and to tan2x+1=sec2x.\tan^2x+1=\sec^2x.



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