Question #144322

Which expression is equivalent to

(sin(θ)+cos(θ))^2?

Expert's answer

(sinΘ+cosΘ)2==sin2Θ+2sinΘcosΘ+cos2Θ==sin2Θ+cos2Θ+sin2Θ==1+sin2Θ(sin\varTheta +cos\varTheta)^2 =\\ = sin^2\varTheta +2sin\varTheta*cos\varTheta +cos^2\varTheta=\\ = sin^2\varTheta+cos^2\varTheta +sin2\varTheta = \\ =1 + sin2\varTheta

answer: 1+sin2Θ1 + sin2\varTheta


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