Answer to Question #144313 in Trigonometry for Shahir Sheikh

Question #144313
Garett is attempting to verify this trig identity. He makes a mistake on one of the lines below. Which line has his first mistake?

sec(θ)−sin(θ)tan(θ)=cos(θ)

1.1cos(θ)−sin(θ)1(sin(θ)cos(θ))=cos(θ)

2. 1cos(θ)−sin(θ)cos(θ)=cos(θ)

3. 1−sin(θ)cos(θ)=cos(θ)

4. cos(θ)=cos(θ)
1
Expert's answer
2020-11-15T17:31:01-0500

3. 1sinθcosθcosθ1- sin\theta cos\theta \neq cos\theta\\

Garette made a mistake on line 3. The equation gives two different results depending on which side being dealt with



1sinθcosθ=1sin2θ2=(cos2θ+sin2θ)tanθcos2θ=cos2θ+sin2θtanθcos2θ1- sin\theta cos\theta = \\ 1 - \dfrac{sin2\theta}{2}= \\ (cos^2\theta + sin^2\theta) - tan\theta\cos^2\theta = \\cos^2\theta + sin^2\theta - tan\theta\cos^2\theta


\therefore The two sides of the equation can't be equal to each other


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