3. 1−sinθcosθ=cosθ
Garette made a mistake on line 3. The equation gives two different results depending on which side being dealt with
1−sinθcosθ=1−2sin2θ=(cos2θ+sin2θ)−tanθcos2θ=cos2θ+sin2θ−tanθcos2θ
∴ The two sides of the equation can't be equal to each other
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