Question #99321
mean weight of 500 student in a certain school is 151pounds and standard deviation is 15 pounds. Assuming that the weights are normally distributed, find how many student weighs
(a) between 120 and 155pounds
(b)mord than 18.5 pounds
1
Expert's answer
2019-11-25T12:59:48-0500

Given that μ=151,σ=15,n=500\mu=151,\sigma=15,n=500

Let X be the random variable denoting the weight of the students.

a) Then we have to find P(120<X<155)P(120<X<155)

Let Z be the standard normal variable, then

Z=(Xμ)/σZ=(X-\mu)/\sigma

When X=120X=120

Z=(120151)/15Z=(120-151)/15

=2.07=-2.07

When X=155X=155

Z=(155151)/15Z=(155-151)/15

=0.27=0.27

P(120<X<155)=P(2.07<Z<0.27)P(120<X<155)=P(-2.07<Z<0.27)

=P(Z<0.27)P(Z<2.07)=P(Z<0.27)-P(Z<-2.07)

=0.6060.019=0.587=0.606-0.019=0.587

Now the number of required student will be (5000.587)244(500*0.587)\approx244


b)

We have to find P(X>18.5)P(X>18.5)

Let Z be the standard normal variable, then

Z=(Xμ)/σZ=(X-\mu)/\sigma

When X=18.5X=18.5

Z=(18.5151)/15Z=(18.5-151)/15

=8.83=-8.83

P(X>18.83)=P(Z>8.83)P(X>18.83)=P(Z>-8.83)

=1P(Z<8.83)=1-P(Z<-8.83)

1\approx1

Now the number of required student will be (5001)=500(500*1)=500


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