If the weights of 600 students are normally distributed with mean of 50 kilograms and a variance of 16kilograms.
a.) Determine the percentage of students with weights lower than 55 kgs.
b.) How many students with weight between 50kgs and 55kgs.
Let "X=" the weight of student: "X\\sim N(\\mu, \\sigma^2)."
Given "\\mu=50kg, \\sigma=\\sqrt{16}kg"
a)
"=P(Z<1.25)=0.89435"
"0.89435(600)=537"
537 students
b)
"-P(Z\\le\\dfrac{50-50}{\\sqrt{16}})=P(Z<1.25)-P(Z\\le 0)"
"=0.89435-0.5=0.39435"
"0.39435(600)=237"
237 students
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