If the weights of 600 students are normally distributed with a mean of 50 kilograms and a variance of 16 kg
b.) How many students with weights between 50 kgs and 55 kgs. (5 points)
Here the everage weights of 600 students is "50" kg with standard deviation "\\sigma=\\sqrt{variance}=4"
Let "X" be a random variable denotes the weight of the students.
Then "X" is normally distributed with mean "50" kg and standard deviation "4" kg.
Therefore we have "\\mu =50" and "\\sigma=4" .
Let us take "Z= \\frac{X-\\mu}{\\sigma}" . Then "Z=\\frac{X-50}{4}".
Now we have to find "P(50<X<55)."
"P(50<X<55)=P(\\frac{50-50}{4}<Z<\\frac{55-50}{4})"
"=P(0<Z<1.25)"
"=0.8944-0.5=0.3944"
So the number of students with weights between "50" kg and "55" kg is "=600*0.3944)=236.64\\approx237"
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