Question #224303

Take all possible samples of size 3 without replacement from population 0, 3, 6, 8, 9, 12, 15. Make a sampling distribution of Proportion odd numbers. Find its mean and Standard Deviation. Verify the properties.


1
Expert's answer
2021-08-09T13:07:58-0400

N= 7

n=3

Number of samples =N!n!(Nn)!= \frac{N!}{n!(N-n)!}

=7!3!(73)!=2106=35= \frac{7!}{3!(7-3)!} = \frac{210}{6}=35



The sampling distribution of Proportion odd numbers


Mean x =x×P(x)=0.428= \sum x \times P(x) = 0.428

SD=(x2×P(x)(x×P(x))2=0.238(0.428)2=0.2380.183=0.055=0.234SD = \sqrt{\sum (x^2 \times P(x) -(\sum x \times P(x))^2} \\ = \sqrt{0.238 -(0.428)^2} \\ = \sqrt{0.238-0.183} \\ = \sqrt{0.055} \\ =0.234


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