Question #223839

consider a population of 5-lb sacks of potatoes for which the variable of interest is the number of potatoes,for which the variable of interest is the number of potatoes.It is a discrete uniform distribution on the intergers 12 through 18.

find the mean ,variance ,and standard deviation of this sampling distribution of the mean for n=2


1
Expert's answer
2021-08-12T14:21:13-0400

The sampling distribution of the sample mean is as follows:



Mean of the sample mean,

E(x)=xP(x)=15E\left(\overline{x}\right)=\sum \:\overline{x}P\left(\overline{x}\right)=15

E(x2)=x2P(x)=227E\left(\overline{x}^2\right)=\sum \:\overline{x}^2P\left(\overline{x}\right)=227


Var(x2)=E(x2)[E(x)]2Var\left(\overline{x}^2\right)=E\left(\overline{x}^2\right)-\left[E\left(\overline{x}\right)\right]^2

Var(x2)=227152=2Var\left(\overline{x}^2\right)=227-15^2=2


Standard deviation of x=SD(x)=Var(x2)\overline{x}=SD\left(\overline{x}\right)=\sqrt{Var\left(\overline{x}^2\right)}

SD(x)=21.414SD\left(\overline{x}\right)=\sqrt{2}\approx 1.414


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS