Question #223839

consider a population of 5-lb sacks of potatoes for which the variable of interest is the number of potatoes,for which the variable of interest is the number of potatoes.It is a discrete uniform distribution on the intergers 12 through 18.

find the mean ,variance ,and standard deviation of this sampling distribution of the mean for n=2


Expert's answer

The sampling distribution of the sample mean is as follows:



Mean of the sample mean,

E(x‾)=∑ x‾P(x‾)=15E\left(\overline{x}\right)=\sum \:\overline{x}P\left(\overline{x}\right)=15

E(x‾2)=∑ x‾2P(x‾)=227E\left(\overline{x}^2\right)=\sum \:\overline{x}^2P\left(\overline{x}\right)=227


Var(x‾2)=E(x‾2)−[E(x‾)]2Var\left(\overline{x}^2\right)=E\left(\overline{x}^2\right)-\left[E\left(\overline{x}\right)\right]^2

Var(x‾2)=227−152=2Var\left(\overline{x}^2\right)=227-15^2=2


Standard deviation of x‾=SD(x‾)=Var(x‾2)\overline{x}=SD\left(\overline{x}\right)=\sqrt{Var\left(\overline{x}^2\right)}

SD(x‾)=2≈1.414SD\left(\overline{x}\right)=\sqrt{2}\approx 1.414


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