Question

the following data given a paired yeilds of two varities that the mean yeilds are equal
Varity A : 45,32,58,57, 60,38,47,51,42,38
Varity B : 47,34,60,59,63,44,49,53,46,41

Answer 1

$H_0:\mu_d=0$

$H_1:\mu_d \ne0$

$t=\frac{\mu_d}{\frac{sd}{\sqrt{n}}}$

$t=\frac{-2.8}{\frac{1.316561}{\sqrt{10}}}$

$=-6.7254$

$CV=T_{0.05,9}=\pm2.2622$ (Two tailed)

Reject the null hypothesis since, the absolute value of the test statistic is greater than the absolute value of the critical value. There is a significant difference between mean yields.