the following data given a paired yeilds of two varities that the mean yeilds are equal
Varity A : 45,32,58,57, 60,38,47,51,42,38
Varity B : 47,34,60,59,63,44,49,53,46,41
1
Expert's answer
2021-08-11T19:28:24-0400
H0:μd=0
H1:μd=0
t=nsdμd
t=101.316561−2.8
=−6.7254
CV=T0.05,9=±2.2622 (Two tailed)
Reject the null hypothesis since, the absolute value of the test statistic is greater than the absolute value of the critical value. There is a significant difference between mean yields.
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