Answer to Question #223727 in Statistics and Probability for Sunny

Question #223727
the following data given a paired yeilds of two varities that the mean yeilds are equal
Varity A : 45,32,58,57, 60,38,47,51,42,38
Varity B : 47,34,60,59,63,44,49,53,46,41
1
Expert's answer
2021-08-11T19:28:24-0400

H0:μd=0H_0:\mu_d=0

H1:μd0H_1:\mu_d \ne0


t=μdsdnt=\frac{\mu_d}{\frac{sd}{\sqrt{n}}}

t=2.81.31656110t=\frac{-2.8}{\frac{1.316561}{\sqrt{10}}}

=6.7254=-6.7254

CV=T0.05,9=±2.2622CV=T_{0.05,9}=\pm2.2622 (Two tailed)

Reject the null hypothesis since, the absolute value of the test statistic is greater than the absolute value of the critical value. There is a significant difference between mean yields.


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