Question

If P.A/ D 0:4 and P.B/ D 0:6, then A and B must be mutually exclusive.

Answer 1

There are two events. P(A/D) & P(B/D).

The sum of the probability of their occurence is:

0.4 + 0.6

which will be equal to 1, A sure event. So the given events would be mutually exclusive