If A and B are any two events of a sample space S, then P.A/ D P.A and B/ P.B/.
Solution:
Given, A and B are any two events of a sample space S.
P(A∪B)=P(A)+P(B)−P(A∩B)P(A\cup B)=P(A)+P(B)-P(A\cap B)P(A∪B)=P(A)+P(B)−P(A∩B)
And, P(A∣B)=P(A∩B)P(B)P(A|B)=\dfrac{P(A\cap B)}{P(B)}P(A∣B)=P(B)P(A∩B)
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